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JSDOEOWIN
JSDOEOWIN
Mathematics
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What is the midpoint of the segment below
Answer :
BSUHAIL03IN
BSUHAIL03IN
Midpoint = ((x1+x2)/2 , (y1+y2)/2)
= ((10/2) , 1/2) = (5, 1/2). Asnwer À
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