307433IN 307433IN

Chemistry

Answered

How many molecules are in 643.21 grams of Mg3(PO4)2?

Answer :

GIZELLERAMIREZ05IN GIZELLERAMIREZ05IN

Answer:

643.21g 1 mol 6.022^23

262.87 g 1 mol

= 1.4735E24 [Mg3(PO4)2]

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