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Mathematics

Answered

The difference of three times Faye's age and four times Joshua's age is 31. If Faye's age is five more than twice Joshua's age, how old is Faye?

Answer :

PALOMA4343IN PALOMA4343IN

She is 31

F-Faye
J-Joshua

F3-J4=31
F=J2+5
(J2+5)(3)-J4=31
J2+5=31
J2+5-5=31-5
J2=26
J2/2=26/2
J=13

F=13(2)+5
F=26+5
F=31

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