Answer:
0.843 mol KNO₃
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
85.2 g KNO₃
Step 2: Identify Conversions
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol
Step 3: Convert
[tex]\displaystyle 85.2 \ g \ KNO_3(\frac{1 \ mol \ KNO_3}{101.11 \ g \ KNO_3} )[/tex] = 0.842647 mol KNO₃
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
0.842647 mol KNO₃ ≈ 0.843 mol KNO₃
