Answer :
Answer:
[tex] \frac{y - 4}{x - ( - 3)} = \frac{8 - 4}{2 - (- 3)} \\ \frac{y - 4}{x + 3} = \frac{4}{5} \\ 5(y - 4) = 4(x + 3) \\ 5y - 20 = 4x + 12 \\ \boxed{4x - 5y + 32 = 0}[/tex]
Answer:
[tex] \frac{y - 4}{x - ( - 3)} = \frac{8 - 4}{2 - (- 3)} \\ \frac{y - 4}{x + 3} = \frac{4}{5} \\ 5(y - 4) = 4(x + 3) \\ 5y - 20 = 4x + 12 \\ \boxed{4x - 5y + 32 = 0}[/tex]