A projectile launched vertically from an altitude of h0​ feet with an initial velocity of v0​ feet per second. The height of the projectile is h(t) feet after t seconds is given by h(t)=−16t2+v0​t+h0​ If h(1)=143 and h(2)=179, find the values of v0​ and h0​. v0​= h0​=