For the following reaction, 2.67 grams of methane (CH4) are allowed to react with 29.1 grams of carbon
tetrachloride.
methane (CH4) (g) + carbon tetrachloride (g) → dichloromethane (CH₂Cl₂) (9)
What is the maximum mass of dichloromethane (CH₂Cl₂) that can be formed?
Mass=
9
What is the FORMULA for the limiting reactant?
What mass of the excess reagent remains after the reaction is complete?
Mass=
g